A C++ question, I know int* foo (void) foo will return a pointer to int type how about int &foo (void) what does it return? Thank a lot!

Nov 25, 2013 · It is a pointer to function that returns int* and accepts int* and pointer to function that returns int* (and accepts undefined number of parameters; see comments).

Sep 25, 2010 · That second memory address, then, is expected to hold an int. Do note that, while you are declaring a pointer to an int, the actual int is not allocated. So it is valid to say int *i = 23, which is …

Jun 16, 2013 · -2 int() is the constructor of class int. It will initialise your variable a to the default value of an integer, i.e. 0. Even if you don't call the constructor explicitly, the default constructor, i.e. int() , is …

int* i, int * i, int*i, and int *i are all exactly equivalent. This stems from the C compiler (and it's compatible C like systems) ignoring white space in token stream generated during the process of parsing the …

Jan 28, 2013 · int array[] = new int[10]; ? Both do work, and the result is exactly the same. Which one is quicker or better? Is there a style guide which recommends one?

Jan 28, 2012 · The real reason that this can happen is that C is a weakly typed language. But unsigned int and int are really different.

int在C语言或者C++语言中代表的是声明一个 整形变量 （其他编程语言中应该也是差不多）。那么声明是整形变量呢，我想它应该符合一下几个特证： 表示范围： − 2 31 -2^ {31} ~ 2 32 2^ {32} （如果没记 …

Aug 24, 2016 · The question "what is the difference between int* and int []?" is a less trivial question than most people will think of: it depends on where it is used. In a declaration, like extern int a[]; it …

Mar 1, 2015 · Например pry = (int*)i; Или такое void(*st)(void) Я знаю, что это указатель, но только если при объявлении переменной.